\(x = \frac{25}{3+4i}\\ x=25\frac{(3-4i)}{(3+4i)(3-4i)}
\\x = 25\frac{(3-4i)}{9+16}\\ x=3-4i\)
x = 3-4i
\(x^2 = (3-4i)^2 = (3)^2 + (4i)^2 -(2)(3)(4i)\\ = 9 -16 -24i = -7 - 24i\\x^2 = -7-24i\)
\(x^3 = x^2\times x = (-7-24i)(3-4i) = -21 + 28i - 72i + (24i\times4i)\\
\Rightarrow-44i-21-96 = -44i-117\)
\(2,-11,44,27\\ 2(-44i-117) -11(-7-24i) + 44 (3-4i) + 27\\
\Rightarrow -88i -334 + 77 + 264i +132 - 176i + 27\\
\Rightarrow 264i -88i - 176i +132+77+27 - 334
\Rightarrow 0i +226-334 = -108\)
Answer = -108
