Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.2k views
in Coordinate Geometry by (37.9k points)
closed by

A triangle ABC is formed by the points A(2, 3), B(-2, -3), C(4, -3). What is the point of intersection of side BC and angular bisector of angle A?

1 Answer

+1 vote
by (36.5k points)
selected by
 
Best answer

Given: △ABC, where A (2, 3), B (- 2, – 3), C (4, – 3). 

Let AD be the bisector to ∠A meeting BC at D.

Then BD : DC = AB : AC 

[∵ The bisector of vertical angle of triangle divides the base in the ratio of other two sides.]

Now D is a point which divides BC in the ratio \(\sqrt{13}:\sqrt{10}\) internally section formula (x, y) =

(By rationalising the denominator of the xcoordinate).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...