Question

Reema wants to check whether the number is even or not but the code below is giving errors. underline the errors and help her write the correct code. 

If(int num%2=0); 

{jTextField1.setText(“even”)

 Else

 jTextField1.setText(“odd”)

Answer 1

If(int num%2=0); 

{jTextField1.settext(“even”) 

Else 

jTextField1.setText(“odd”) 

Correct code :

if(int num%2==0) 

jTextField1.setText(“even”); 

else 

jTextField1.setText(“odd”); 

(8 errors to be marked and corrected )