Mathematical proof of law of conservation of energy :
At A Consider a body of mass m at A at a height h above the ground level.
P.E. = mgh K.E. = 0 at rest.
P.E. + K.E. = mgh + O = mgh …………….. (i)
Let it fall from A to B covering a distance x and still at (h-x) above ground.
In doing so
v2 – u2 = 2gx
v2 – 0 = 2gx
v2 = 2gx …(a)
At B P.E = mg (h – x)
AT C P.E + K.E = 0 + mgh
P.E. + K.E. = mgh
Thus we find sum of P.E. + K.E. at A, B, C remains same mgh
Hence varifies the law of can servation of energy.
