Question

67.2 litres of H₂ combines with 44.8 litres of N₂ to form NH₃ : N₂ (g) + 3H₂ (g) → 2NH₃ (g). Calculate the vol. of NH₃ produced. What is the substance, if any, that remains in the resultant mixture ?

Answer 1

3 volume of hydrogen produces 2 volume of ammonia

67.2 litres of hydrogen produces = 2/3 x 67.2 = 44.8 litres

3 volume of hydrogen reacts with 1 volumes of nitrogen

67.2 litres of hydrogen reacts with = 1/3 x 67.2 = 22.4 litres

Nitrogen lefts = 44.8 - 22.4 = 22.4 litres