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The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs. 18.

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The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs. 18. Find the missing frequency f.

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\(\overline{x}=\frac{\Sigma f_ix_i}{\Sigma f_i}\)

xi = 18 (given) 

\(⇒ 18=\frac{752+20f}{(44+f)}\)

18 (44 + f) = 752 + 20 f 

⇒ 20f- 18f= 792-752 

⇒ 2f = 40 

∴ f = 40/2 = 20.

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is it ok is it correct

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