LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
in Statistics by (38.0k points)
closed by

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs. 18. Find the missing frequency f.

2 Answers

+1 vote
by (39.7k points)
selected by
Best answer

\(\overline{x}=\frac{\Sigma f_ix_i}{\Sigma f_i}\)

xi = 18 (given) 

\(⇒ 18=\frac{752+20f}{(44+f)}\)

18 (44 + f) = 752 + 20 f 

⇒ 20f- 18f= 792-752 

⇒ 2f = 40 

∴ f = 40/2 = 20.

+1 vote
by (25 points)

is it ok is it correct

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.