Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
171 views
in Oscillations and waves by (30 points)
edited by

The displacement equation of SHM is y = 0.5 (sin 3πt + √3 cot 3πt). Find Amplitude, Angular frequency, Period of oscillation, velocity and acceleration.

Please log in or register to answer this question.

1 Answer

0 votes
by (41.1k points)

y = 0.5 (sin 3πt + √3 cot 3πt)

y = 0.5 x 2 ( \(\cfrac12\) sin 3πt + \(\cfrac{\sqrt3}2\) cot 3πt)

y = 1 ( cot \(\cfrac{\pi}3\) sin 3πt - sin \(\cfrac{\pi}3\) cot 3πt)

y = sin( 3πt + \(\cfrac{\pi}3\))

Comparing equation

y = A sin (ωt + θ)

Then amplitude A = 1

Angular frequency ω = 3π rad/sec

Time period T = \(\cfrac{2\pi}ω\)

T = \(\cfrac{2\pi}{3\pi}\)

T = \(\cfrac23\) sec

Acceleration a = Aω2

= 1 x (3π)2

a = 9π2 m/s2

Velocity v = Aω

v = 1 x 3π

v = 3π m/s

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...