Diagram shows 6 identical air capacitors connected to an ideal battery (V). In this condition, charge on capacitor \( C_{6} \) is \( Q_{1} \). Now a dielectric whose dielectric constant is 2 , is put between the plates of \( C_{4} \) so that it occupies the entire space between the plates. Now charge on \( C _{6} \) becomes \( Q _{2} \). Then \( \frac{ Q _{1}}{ Q _{2}} \) should be :-