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A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C12H22O11)

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A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C12H22O11) 

Calculate

(i) molal concentration and

(ii) mole-fraction of sugar in the syrup

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1 Answer

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Given, weight of sugar syrup = 214.2 g weight of sugar (C12H22O11) in sugar syrup = 34. 2g

.'.  Wt of solvent (water) = 214.2 - 34.2 = 180.0 g 

(i) .'. Molal conc. (molality)

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