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Solve 2x + 3y = 12 and 3x + 2y = 13 in the method of substitution.

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The given equations are 

2x + 3y – 12 ………….. (1) 

3x + 2y = 13 ………….. (2) 

∴ 2x = 12 – 3y [∵From (1)] 

x = \(\frac{12-3y}{2}\)……….. (3) 

Substitute this value of x in given equation (2) we get

⇒ 36 – 5y = 13 x2 = 26 

⇒ -5y = 26 -36 = – 10 

∴ 5y = 10 and y = \(\frac{10}{2}\) = 2 

Then from equation (3)

∴ x = 3 and y = 2 are the solution for given pair of linear equations.

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