# Find the roots of the quadratic equation (3x – 2)^2 – 4(3x – 2) + 3 = 0.

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Find the roots of the quadratic equation (3x – 2)2 – 4(3x – 2) + 3 = 0.

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(3x – 2)2 – 4(3x – 2) + 3 = 0

9x2 + 4 – 12x – 12x + 8 + 3 = 0

9x2 – 24x +15 = 0

3x2 – 8x + 5 = 0

3x2 – 3x – 5x + 5 = 0

3x(x – 1) – 5 (x – 1) = 0

(x- 1) (3x – 5) = 0

x = 1 (or) x = $\frac{5}{3}$

Roots of quadratic equation are 1, $\frac{5}{3}$ .