In an A.P. the ‘n’ th term = an
= a + (n – 1) d
Then a7 = a + (7 – 1) d
= a + 6d = 13 …………..(1)
and a3 = a + (3 – 1) d
= a + 2d = 7 ………….. (2)
Now solving equations (1) & (2) in elimination method
Then a + 2d = 7
a + 2 (1.5) = 7 ⇒ a + 3 = 7
and a = 7 – 3 = 4
So a = 4 and d = 1.5