Let the number be ‘x’ say.
8 times of a number = 8 × x = 8x
If 10 is reduced from 8x then 8x – 0
6 times of a number = 6 × x = 6x
If 4 is added to 6x then 6x + 4
According to the sum,
8x – 10 = 6x + 4
⇒ 8x – 6x = 4 + 10
⇒ 2x = 14
⇒ x = 7
∴ The required number = 7