Let P and Q be the points of trisection of AB, i.e., AP = PQ = QB.
Therefore, P divides AB internally in the ratio 1 : 2.
Therefore, the coordi¬nates of P are (by applying the section formula)
Now, Q also divides AB internally in the ratio 2 : 1. So, the coordinates of Q are
Therefore, the coordinates of the points of trisection of the line segment are P(3, – 2) and Q(4, – 5).