0 votes
22 views
in Linear Equations by (41.9k points)
closed by

Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has 7 sweets left. How many did he have to start with?

1 Answer

+1 vote
by (43.1k points)
selected by
 
Best answer

Number of sweets with Sekhar = x say. 

Number of sweets given to Renu = 1/4 × x = x/4

Number of sweets given to Raji = 5 

Till he has 7 sweets left.

x – ( x/4 + 5) = 7 

⇒ x – x/4 – 5 = 7 

⇒ x – x/4 = 7 + 5 = 12 

\(\frac{4x\,-\,x}{4}\) = 12 

⇒ 3x/4 = 12

⇒ x = 12 × 4/3 = 16 

∴ x = 4 × 4 = 16

∴ Number of sweets with Sekhar at the beginning = 16

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...