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Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has 7 sweets left. How many did he have to start with?

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Number of sweets with Sekhar = x say. 

Number of sweets given to Renu = 1/4 × x = x/4

Number of sweets given to Raji = 5 

Till he has 7 sweets left.

x – ( x/4 + 5) = 7 

⇒ x – x/4 – 5 = 7 

⇒ x – x/4 = 7 + 5 = 12 

\(\frac{4x\,-\,x}{4}\) = 12 

⇒ 3x/4 = 12

⇒ x = 12 × 4/3 = 16 

∴ x = 4 × 4 = 16

∴ Number of sweets with Sekhar at the beginning = 16

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