Let the shortest side = ‘x’ m
then its hypotenuse = (2x + 6) m
Third side = 2x + 6 – 2 = (2x + 4) m
then from Pythagoras theorem, we have
but ‘x’ being the length cannot be negative.
So x ≠ -2, we consider x = 10 only then the
shortest side = x = 10m
third side = 2x + 4 = 24 m
hypotenuse = 2x + 6 = 26m