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The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find 

(i) its inner curved surface area 

(ii) the cost of plastering this curved surface at the rate of Rs. 40 per m2

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Inner diameter of the circular well, d = 3.5 m

Thus its radius, r = d/2 = 3.5/2 = 1.75 m

Depth of the well (height) = 10 m 

i) Inner C.S.A. = 2πrh

= 2 × 22/7 × 1.75 × 10

= 110 m2

ii) Cost of plastering at the rate of 

₹ 40 / m2 = 110 × 40 = ₹ 4400

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