In the given ΔABC, DE || BC is given.
So from Thales theorem,
\(\frac{AD}{DB}=\frac{AE}{EC}\)
In this problem, AD = DB = 3.4 is given.
And also AC = 14 is given.
So \(\frac{AD}{DB}=\frac{AE}{EC}\)
⇒ \(\frac{3.4}{3.4}=\frac{AE}{EC}\)
⇒ AE = EC
But AC = 14 is given.
AC = AE + EC = 2AE = 14
⇒ AE = EC = 7 cm