Question

Calculate the molality of 1 L solution of 93 % H₂SO₄. (weight/volume).The density of the solution is 1.84 g/mL.

Answer 1

Given, 93% H₂SO₄ solution (weight/volume).

It means 93 g of H₂SO₄ present in 100 mL of solution, therefore,

weight of H₂SO₄ = 93 g

Volume of solution = 100 mL 

.'. Weight of solution = 100 x 1.84 = 184 g