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A 2.0 g sample of a mixture containing sodium carbonate, sodium bicarbonate and sodium sulphate is gently heated till the evolution of CO2 ceases. The volume of CO2 at 750 mm Hg pressure and at 298 K is measured to be 123.9 mL. A 1.5 g of the same sample requires 150 mL of (M/10) HCI for complete neutralization. Calculate the percentage composition of the components of the mixture.

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According to ideal gas equation,

On heating a mixture of NaHCO3,Na2CO3 and Na2SO4, only NaHCO3 is decomposed according to following equation.

Thus, the weight of NaHCO3 in the mixture = 0.84

Hence, the percentage of NaHCO3 in the mixture

= 0.84/2.0 x 100 = 42.0 %

When 1.5 g of mixture is treated with HCl. Therefore, Na2SOis not reacted while Na2COis reacted with HCI as follow :

Suppose, the amount of Na2CO3 in 1.5 g of mixture is.y g.

So, the amount of HCl used with Na2CO3 = 73/106 x y g

NaHCO3 reacts with HCl as follows :

Thus, percentage of Na2SO4 in the mixture = 100 -% of NaHCO3 - % of  Na2CO3 = 100 - 42 - 26.5 = 31.5 %

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