Radius of the conical sent (r) = 5 m.
Height of the tent (h) = 12 m.
∴ Slant height of the cone
Now, surface area of the tent = πrl
= \(\frac{22}{7}\) × 5 × 13 = \(\frac{1430}{7}\) m2
Area of the canvas used = \(\frac{1430}{7}\) m2
It is given that the width of the canvas = 2m.
Length of the canvas used = \(\frac{Area}{Width}\)
= \(\frac{1430}{7}\times\frac{1}{2}\)
= 102.14 m