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In the figure, PR and QS are two diameters. Is PQ = RS ?

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‘O’ is the centre of the circle.

[ ∵ PR, QS are diameters] 

OP = OR (∵ radii) . 

OQ = OS (∵ radii) 

∠POQ = ∠ROS [vertically opp. angles] 

∴ ΔOPQ ≅ ΔORS [SAS congruence] 

∴ PQ = RS [CPCT]

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