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If 4 sin2 θ – 1 = 0 then find θ’ (θ < 90) also, find the value of θ and the value of cos2 θ + tan2 θ

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Given 4 sin2 θ – 1 = 0 

⇒ 4 sinθ = 1 

sinθ = 1/4

⇒ sin θ = ± \(\sqrt{\frac{1}{4}}=± \,\frac{1}{2}\)

Given θ is less than 90°

sin θ = \(\frac{1}{2}\)

sin θ = sin30° ⇒ θ = 30°

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