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Na2SO4 + Pb(NO3 )2 → PbSO4 + 2NaNO3 When excess » lead nitrate solution was added to a solution of sodium sulphate, 15.15 g of lead sulphate were precipitated. What mass of sodium sulphate was present in the original solution. (H = 1 ; C = 12 ; O = 16 ; Na = 23; S = 32 ; Pb = 207)

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Now 366 of PbSO4 is obtainde from 142 g of Na2SO4

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