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10g. of a mixture of NaCI and anhydrous Na2SO4 is dissolved in water. An excess of BaCl2 soln. is added and 6.99 g. of BaSO is precipitated according to the equation : Na2SO4 + BaCl2 → BaSO4 ↓+ 2NaCl. Calculate the percentage of sodium sulphate in the original mixture. (O = 16 ; Na = 23 ; S = 32; Ba = 137)

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Now 223 g of BaSO4 is obtained from 142 g Na2SO4

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