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in Squares And Square Roots by (41.5k points)
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What smallest number should 7803 be multiplied with so that the product becomes a perfect cube?

1 Answer

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by (40.1k points)
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Best answer

The prime factorization of 7803 = (3 × 3 × 3) × (17 × 17)

∴ From the above product 17 is left in the triplet. 

∴ 17 should be multiplied to 7803 then we will get a perfect cube number.

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