Given equation = 5x + 3y – 7 = 0
x = 2 – α and y = 2 + α
∴ 5(2 – α) + 3(2 + α) – 7 = 0
⇒ 10 – 5α+ 6 + 3α – 7 = 0
⇒ 9 – 2α = 0
⇒ 2α = 9 ⇒ α = 9/2 = 4.5
Given equation 3x – 2y + 6 = 0
x = 2β + 1 and y = β – 1
∴ 3(2β + 1)- 2(β – 1) + 6 = 0
⇒ 6β + 3 – 2β + 2 + 6 = 0
⇒ 4β + 11 = 0 ⇒ β = -11/4
∴ α + β = 9/2 - 11/4 = \(\frac {18-11}{4} = \frac {7}{4}\)