# ​ In the given figure ‘O’ is the centre of the circle. AB is a chord. In ΔOAB show that ∠OAB = ∠OBA ​

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In the given figure ‘O’ is the centre of the circle. $\overline {AB}$ is a chord. In ΔOAB show that ∠OAB = ∠OBA

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In ΔAOB, OA = OB = radius of circle In an isosceles triangle angles opposite to equal sides are equal angles.

∴ ∠OAB = ∠OBA