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If a dice with six faced rolled randomly find. 

i) The probability of getting an even number on the top face.

ii) The probability of getting a prime number on the top face. 

iii) The probability of getting 7 on the top face 

iv) The probability of getting a number on the top face which have the sum of the factors of that number is twice to that number. (Which is called as a perfect number)

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i) Even numbers in outcomes = 2, 4, 6 = 3 

∴ Required probability = 4/6 = 2/3

ii) Prime numbers = 1, 2, 3, 5 = 4 

∴ Required probability = 4/6 = 2/3

iii) Getting ‘7’ on top = 0 

∴ This is impossible event.

iv) Sum of the factors of that number is twice to that numbers = 6

∴ Required probability = 1/6

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