Q1.
(i) \(24x < 100\)
\(⇒\) \(x < \frac{100}{24}\) (Dividing both sides by 24)
\(⇒\) \(x < \frac{25}{6} \)
The natural numbers less than 4 are 1, 2, 3
∴ The solution set is {1, 2, 3}
(ii) The integers less than 4 are … -3, -2, -1, 0, 1, 2, 3, 4
∴ The solution set is {… -3, -2, -1, 0, 1, 2, 3, 4}.
Q2.
(i) \(-12x > 30 \)
\(⇒\) \(x > \frac{-30}{12} \)
\(⇒\) \(x > \frac{-5}{2} \)
There is no natural number less than, \(\frac{-5}{2} \) thus there is no solution for this inequality.
(ii) The integers less than \(\frac{-5}{2} \) are … -5, -4, -3
The solution set is {…-5, -4, -3}.
Q3.
Sol:- \( 3(1 – x)< 2 (x + 4)\)
\(⇒\) \(3 - 3x < 2x + 8\)
\(⇒\) \(3 < 5x + 8\)
\(⇒\) \(-5 < 5x\)
\(⇒\) \(x > - 1\)
\(∴ x ∈ (-1, ∞)\)
Q4.
Let the minimum marks be x. Then,
\(⇒\) \(\frac{70 + 75 + x}{3} ≥ 60 \)
\(⇒\) \(\frac{145 + x}{3} ≥ 60 \)
\(⇒\) \(145 + x ≥ 180\)
\(⇒\) \(x ≥ 35\)
Ravi should get minimum 35 marks in the third set to have an average of at least 60 marks.
Q5.
Let the minimum marks scored by Sunita be x. Then,
\(⇒\) \(\frac{87 + 92 + 94 + 95 + x}{5} ≥ 90 \)
\(⇒\) \(\frac{368 + x}{5} ≥ 90 \)
\(⇒\) \(368 + x ≥ 450 \)
\(⇒\) \(x ≥ 82\)
The minimum marks scored by Sunita must be 82.