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Four ships A, B,C and D are at sea in the following relative positions: B is on the straight line segment AC, B is due North of D and D is due West of C. The distance between B and D is 2 km. ∠BDA = 40°, ∠BCD = 25°. What is the distance between A and D? [Take sin 25° = 0.423]

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In ΔADC, we have ∠ADC = 40° + 90° = 130°

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