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0 votes
1.1k views
in Mathematics by (88.9k points)

A semicircular arch AB of length 2L and a vertical tower PQ are situated in the same vertical plane. The feet A and B of the arch and the base Q of the tower are at the same horizontal level with B between A and Q. A man at A finds the tower hidden from his view due to the arch. He stands crawling up the arch and just sees the top most point P of the tower after covering a distance L/2 along the arch. He crawls further to the top most point of the arch and notes the angle of elevation of p at be θ. 

Compute the height of the tower in terms of L and θ.

1 Answer

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by (79.0k points)
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Best answer

When a man is at M then are AM subtends an angle of π/4 at O. From M we can just see the top of the tower so that MP is a tangent to arc at M.

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