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in Linear Equations by (37.8k points)
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Jeevan is 3 years younger than his brother Sasi. If the sum of their present ages is 19 years. What are their present ages ?

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Best answer

Let the present age of Sasi is x years.

The present age of Jeevan = (x – 3) years 

Sum of their present ages = 19 

⇒x + x – 3 = 19 

⇒ 2x – 3 = 19 

⇒ 2x – 3 + 3 = 19 + 3 (Add 3 on both sides) 

⇒ 2x = 22

⇒ 2x/2 = 22/2 (Divide by 2 on both sides)

⇒ x = 11 years

∴ Present age of Sasi x = 11 years 

Present age of Jeevan = x – 3 

= 11 – 3 = 8 years

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