The correct option (d) 75mL of (M/5)HCI + 25mL of (M/5) NaOH
Explanation:
75mL of M/5HCl + 25mL of M/5 NaOH
Meq of HCl = 15 (∴ Mol. wt. and Eq. wt. of HCl or NaOH are same)
Meq of NaOH = 5
Hence, in solution 10meq of HCl are remained in 100mL solution.
So, concentration of HCl in mixture = 10/100M = M/10