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Find the sum of integers from 11 to 1000 which are divisible by 3.

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Sum of the numbers which are divisible by 3 from into 1000 

= 12 + 15 + ……….. + 099 

= 3(4 + 5 + ……….. + 333) 

= 3(1 + 2 + ……….. + 333) – 3(1 + 2 + 3)

= 999 × 167 – 9 × 2 

= 166833 – 18 

= 166815

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