Question

The solubility product of Ag₂C₂O₄ at 25°C is 1.29 x 10^-11 mol³L^-3. A solution of K₂C₂O₄ containing 0.520 mole in 500mL water is shaken at 25°C with excess of Ag₂CO₃ till the following equilibrium is reached

Ag₂CO₃ + K₂C₂O₄ ⇋Ag₂C₂O₄ + K₂CO₃

At equilibrium, the solution contains 0.0358 mole of K₂CO₃. Assuming the degree of dissociation of K₂C₂O₄ and K₂CO₃ to be equal, calculate the solubility product of Ag₂CO₃.

Answer 1

at equilibrium,