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Solve the following. 

(i) 2.3 ÷ 100 

(ii) 0.45 ÷ 5 

(iii) 44.3 ÷ 10 

(iv) 127.1 ÷ 1000 

(v) 7 ÷ 35 

(vi) 88.5 ÷ 0.15 

(vii) 0.4 ÷ 20

1 Answer

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Best answer

(i) 2.3 ÷ 100 = \(\frac {23}{100}\) ÷ 100 = \(\frac {23}{100}\) x \(\frac {1}{100}\) = \(\frac {23}{1000}\) = 0.023

(ii) 0.45 ÷ 5 =  \(\frac {45}{100}\) ÷ 5 = \(\frac {45}{100}\) x \(\frac 15\) = \(\frac {9}{100}\) = 0.09

(iii) 44.3 ÷ 10 = 44.3 × \(\frac {1}{10}\) = 4.43

(iv) 127.1 ÷ 1000 = 127.1 × \(\frac {1}{1000}\) = 0.1271

(v) 7 ÷ 35 = 7 × \(\frac {1}{3.5} = \frac {7 \times 10}{3.5\times 10} = \frac {70}{35}\) = 2

(vi) 88.5 ÷ 0.15 = \(\frac {885}{10}\) ÷  \(\frac {15}{100}\) = \(\frac {885}{10}\) x \(\frac {100}{15}\) = 590

(vii) 0.4 ÷ 20 = \(\frac {4}{10}\) ÷ 20 = \(\frac {4}{10}\) x \(\frac {1}{20}\) = \(\frac {1}{10\times 5} = \frac {1}{50}\) = 0.02

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