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+1 vote
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in Mathematics by (51.7k points)

The sum of the areas of two squares is 468 m2 . If the difference of their perimeters is 24 m, find the sides of the two squares.

1 Answer

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by (266k points)
 
Best answer

Let x be the length of the side of the first square and y be the length of side of the second square.

Putting the value of x in terms of y from equation (ii), in equation (i), we get

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