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+1 vote
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in Physics by (121k points)
Focal length of a lens in air is f. Refractive index of the lens is `mu`. Focal length changes to `f_(1)` if lens is immersed in a liquid of refractive index `(mu)/(2)` and it becomes `f_(2)` if the lens is immersed in a liquid of refractive index `2 mu`. Then
A. `f_(1) = (f)/(2)`
B. `f_(2) = -2f`
C. `f_(2) = -(3f)/(2)`
D. Data is insufficient

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1 Answer

0 votes
by (121k points)
Correct Answer - D

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