Question

In the adjacent figure, BD and CE are altitudes of ΔABC such that BD = CE. 

i) State the three pairs of equal parts in ΔCBD andΔBCE.

ii) Is ΔCBD ≅ ΔBCE ? Why or why not ?

iii) Is ∠DBC = ∠EBC ? Why or why not ?

Answer 1

i) ∠CDB ≅ ∠BEC (Right angle) 

BD = CE (Side) 

BC = BC common/hypotenuse

ii) Yes, 

ΔCBD ≅ ΔBCE by R.H.S congruence

iii) No, 

∠DBC ≠ ∠EBC