Question

Construct ΔABC in which AB = 5cm, ∠B = 45° and BC = 6cm.

Answer 1

AB = 5cm, ∠B = 45° and BC = 6cm.

Step -1: 

Draw a rough sketch of a triangle and label it with the given measurements. 

Step -2: 

Draw a line segment AB of length 5cm. 

Step -3: 

Draw a ray \(\overrightarrow {BY}\) making an angle 45° with AB. 

Step -4: 

Draw an arc of radius 6 cm from B, which cuts  \(\overrightarrow {BY}\) at C. 

Step -5: 

Join A, B to get the required ΔABC.