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\( 4 x^{4}-3 x^{3}-2 x^{2} \div x-1 \)

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Find:

\( 4 x^{4}-3 x^{3}-2 x^{2} \div x-1 \)

\(\frac{4x^4-3x^3-2x^2}{x-1}\)

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1 Answer

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\(\frac{4x^4-3x^3-2x^2}{x-1}\) = 4x3 + x2 - x - 1

\(\therefore\) \(\frac{4x^4-3x^3-2x^2}{x-1}=4x^3+x^2-1-\frac{1}{x^{-1}}\)

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