Given quadratic equation is
3x2 - 2\(\sqrt2\) - 2\(\sqrt3\) = 0
By comparing with ax2 + bx + c = 0 we get
a = 3, b = -2\(\sqrt2\) and c = -2\(\sqrt3\)
\(\therefore\) Discriminant = b2 - 4ac
= (-2\(\sqrt2\))2 - 4 x 3 x - 2\(\sqrt3\)
= 8 + 24\(\sqrt3\)
= 8(1 + 3\(\sqrt3\)) > 0