BThe formula of compound will be AB2O4
Explanation:
We all know that oxygen like bigger molecules occupy the lattice points. The effective number of atoms in a CCP unit cell is 8 x 1/8 + 6 x 1/2 = 4
Also the total number of tetrahedral voids (X is presnt) in CCP is 8 so no. of divalent ions = 8/8 = 1
Number of Octahedral voids (Y is present) are 4 so 1/2 of no. of divalent ion will be 4/2 = 2
Number of oxide = present at corners + at face centre = 8 x 1/8 + 6 x 1/2 = 4
So formula of compound will be AB2O4