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+2 votes
5.0k views
in Computer by (71.2k points)

Derive a Canonical SOP expression for a Boolean function F(X,Y,Z) represented by the following truth table:

X Y Z F(X,Y,Z)
0 0 0 1
0 0 1 1
0 1 0 0
0 1 1 0
1 0 0 1
1 0 1 0
1 1 0 0
1 1 1 1

1 Answer

+3 votes
by (76.3k points)
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Best answer

F(X,Y,Z)= X’Y’Z’+X’Y’Z+XY’Z’+XYZ

OR

F(X,Y,Z)=Σ(0,1,4,7)

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