Correct option is: (D) \(\frac{2.303 \ RT}{F}\)
According to Nernst equation
E = \(E_0 - \frac {RT}{nF}\) ln Q
or E = \(E_0 - \frac {8.314 \times 298 \times 2.303}{n\times 96500}\) log Q.
E = \(E_0 - \frac {0.0592}{n}\) log Q.
Therefore, \(\frac{2.303 \ RT}{F}\) = 0.0592