Let `Ea n dF`
be tow independent events. The probability that exactly one of them
occurs is 11/25 and the probability if none of them occurring is 2/25. If `P(T)`
deontes the probability of occurrence of the event `T ,`
then
`P(E)=4/5,P(F)=3/5`
`P(E)=1/5,P(F)=2/5`
`P(E)=2/5,P(F)=1/5`
`P(E)=3/5,P(F)=4/5`
A. `P€=(4)/(5),P(F)=(3)/(5)`
B. `P€=(1)/(5),P(F)=(2)/(5)`
C. `P€=(2)/(5),P(F)=(1)/(5)`
D. `P€=(3)/(5),P(F)=(4)/(5)`
