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in Probability by (122k points)
Box 1 contains three cards bearing numbers 1, 2, 3; box 2 contains five cards bearing numbers 1, 2, 3,4, 5; and box 3 contains seven cards bearing numbers 1, 2, 3, 4, 5, 6, 7. A card is drawn from each of the boxes. Let `x_i` be the number on the card drawn from the ith box, i = 1, 2, 3. The probability that `x_1+x_2+x_3` is odd is The probability that `x_1, x_2, x_3` are in an aritmetic progression is
A. `(9)/(105)`
B. `(10)/(105)`
C. `(11)/(105)`
D. `(7)/(105)`

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1 Answer

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by (121k points)
Correct Answer - B

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