For three events `A ,B`
and `C ,P`
(Exactly one of `A`
or `B`
occurs) `=P`
(Exactly one of `B`
or `C`
occurs) `=P`
(Exactly one of `C`
or `A`
occurs) `=1/4`
and `P`
(All the three events occur simultaneously) `=1/6dot`
Then the probability that at least one of the
events occurs, is :
`7/(64)`
(2) `3/(16)`
(3) `7/(32)`
(4)
`7/(16)`
A. `(3)/(16)`
B. `(7)/(32)`
C. `(7)/(16)`
D. `(7)/(64)`
